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OcRam
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Posted on 10-26-07 1:02
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Using
all the digits 1 to 9, each once only, make two numbers, one of which is exactly
twice the other.
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raascal
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Posted on 10-26-07 11:09
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OcRam must be laughing looking at screen. :)
In the meanwhile, I give 100 points to all participants.
Thank you.
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MAKURAMANCHE
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Posted on 10-26-07 11:12
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YEA I THINK SO... I AM MAKING THIS THING MORE CONFUSING WID MY EACH POST AND MY POSTS ARE ABOUT TO RUN OUT... I HAVE ALREADY USED 50 THIS MAKES 51 NOW I SHOULD USE MY POSTS WISELY LOL
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Aalu Jasto
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Posted on 10-26-07 11:18
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in both cases .. we got the answer .. from prakash ji and debonair .. Macuramamche ... U really speak too fast .. just think twice before you conclude other wrong ... by the way ..how old r u ? I think u r not more than 20 years...and must be high school student ..
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MAKURAMANCHE
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Posted on 10-26-07 11:22
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YA I AM HI SKOOLER... WHY??? AND 18 YRS OLD... TURNED 18 EXACTLY 2 WEEKS AGO
Last edited: 26-Oct-07 11:23 AM
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marconi
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Posted on 10-26-07 12:13
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raascal was correct. I have another answer too, 13458 is exactly twice 6729.
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Kalki Kapil
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Posted on 10-26-07 12:19
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123456789:
First Set: 246913578
Second: 426913578
QED!!!!
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arcane
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Posted on 10-26-07 12:21
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Hey guys you all are giving the wrong answers. You may not have understood the question clearly. I know the answer so I am clarifying the question. You should have all digits consisting of 1 to 9 without repitition. You cannot take only some (say 13458 ). The number should contain nine digits consisting 1 to 9 and the double of it also should have 9 digits between 1 to 9 without repitition in both.
so you cannot say 6729 and its double is 13458 or similar which has less than nine digits.
The answer given by debonair is right.
123456789 and its double 246913578 each with 9 digits and no repitition
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Kalki Kapil
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Posted on 10-26-07 12:23
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Repeating:
First Set:
123456789 x2=246913578
Second Set:
213456789x2=426913578
Is it correct?
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OcRam
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Posted on 10-26-07 4:40
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I was expecting answer that was given by Raascal and Marconi. But I m happy to get so many answers which are also correct as per the question. Thank you.
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